81c^2+198c+121=0

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Solution for 81c^2+198c+121=0 equation:


Simplifying
81c2 + 198c + 121 = 0

Reorder the terms:
121 + 198c + 81c2 = 0

Solving
121 + 198c + 81c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(11 + 9c)(11 + 9c) = 0

Subproblem 1

Set the factor '(11 + 9c)' equal to zero and attempt to solve: Simplifying 11 + 9c = 0 Solving 11 + 9c = 0 Move all terms containing c to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + 9c = 0 + -11 Combine like terms: 11 + -11 = 0 0 + 9c = 0 + -11 9c = 0 + -11 Combine like terms: 0 + -11 = -11 9c = -11 Divide each side by '9'. c = -1.222222222 Simplifying c = -1.222222222

Subproblem 2

Set the factor '(11 + 9c)' equal to zero and attempt to solve: Simplifying 11 + 9c = 0 Solving 11 + 9c = 0 Move all terms containing c to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + 9c = 0 + -11 Combine like terms: 11 + -11 = 0 0 + 9c = 0 + -11 9c = 0 + -11 Combine like terms: 0 + -11 = -11 9c = -11 Divide each side by '9'. c = -1.222222222 Simplifying c = -1.222222222

Solution

c = {-1.222222222, -1.222222222}

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